(x-4)(x+2)(x^2-1)=0

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Solution for (x-4)(x+2)(x^2-1)=0 equation:


Simplifying
(x + -4)(x + 2)(x2 + -1) = 0

Reorder the terms:
(-4 + x)(x + 2)(x2 + -1) = 0

Reorder the terms:
(-4 + x)(2 + x)(x2 + -1) = 0

Reorder the terms:
(-4 + x)(2 + x)(-1 + x2) = 0

Multiply (-4 + x) * (2 + x)
(-4(2 + x) + x(2 + x))(-1 + x2) = 0
((2 * -4 + x * -4) + x(2 + x))(-1 + x2) = 0
((-8 + -4x) + x(2 + x))(-1 + x2) = 0
(-8 + -4x + (2 * x + x * x))(-1 + x2) = 0
(-8 + -4x + (2x + x2))(-1 + x2) = 0

Combine like terms: -4x + 2x = -2x
(-8 + -2x + x2)(-1 + x2) = 0

Multiply (-8 + -2x + x2) * (-1 + x2)
(-8(-1 + x2) + -2x * (-1 + x2) + x2(-1 + x2)) = 0
((-1 * -8 + x2 * -8) + -2x * (-1 + x2) + x2(-1 + x2)) = 0
((8 + -8x2) + -2x * (-1 + x2) + x2(-1 + x2)) = 0
(8 + -8x2 + (-1 * -2x + x2 * -2x) + x2(-1 + x2)) = 0
(8 + -8x2 + (2x + -2x3) + x2(-1 + x2)) = 0
(8 + -8x2 + 2x + -2x3 + (-1 * x2 + x2 * x2)) = 0
(8 + -8x2 + 2x + -2x3 + (-1x2 + x4)) = 0

Reorder the terms:
(8 + 2x + -8x2 + -1x2 + -2x3 + x4) = 0

Combine like terms: -8x2 + -1x2 = -9x2
(8 + 2x + -9x2 + -2x3 + x4) = 0

Solving
8 + 2x + -9x2 + -2x3 + x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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